11343412040 has 32 divisors (see below), whose sum is σ = 26116231680. Its totient is φ = 4431844032.

The previous prime is 11343412033. The next prime is 11343412049. The reversal of 11343412040 is 4021434311.

It is a junction number, because it is equal to n+sod(n) for n = 11343411997 and 11343412015.

It is not an unprimeable number, because it can be changed into a prime (11343412049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3295784 + ... + 3299223.

It is an arithmetic number, because the mean of its divisors is an integer number (816132240).

Almost surely, 2^11343412040 is an apocalyptic number.

11343412040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11343412040 is an abundant number, since it is smaller than the sum of its proper divisors (14772819640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11343412040 is a wasteful number, since it uses less digits than its factorization.

11343412040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6595061 (or 6595057 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 11343412040 its reverse (4021434311), we get a palindrome (15364846351).

The spelling of 11343412040 in words is "eleven billion, three hundred forty-three million, four hundred twelve thousand, forty".