Base | Representation |
---|---|
bin | 10101001000001111… |
… | …01110001010110110 |
3 | 1002021112122112211201 |
4 | 22210013232022312 |
5 | 141212404002014 |
6 | 5113332523114 |
7 | 551046332362 |
oct | 124407561266 |
9 | 32245575751 |
10 | 11343422134 |
11 | 48a107aa40 |
12 | 2246a8049a |
13 | 10ba119805 |
14 | 7987482a2 |
15 | 465cc8e74 |
hex | 2a41ee2b6 |
11343422134 has 8 divisors (see below), whose sum is σ = 18561963528. Its totient is φ = 5156100960.
The previous prime is 11343422113. The next prime is 11343422143. The reversal of 11343422134 is 43122434311.
It is a happy number.
11343422134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-4 number, since 4×113434221344 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257805027 + ... + 257805070.
It is an arithmetic number, because the mean of its divisors is an integer number (2320245441).
Almost surely, 211343422134 is an apocalyptic number.
11343422134 is a deficient number, since it is larger than the sum of its proper divisors (7218541394).
11343422134 is a wasteful number, since it uses less digits than its factorization.
11343422134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 515610110.
The product of its digits is 6912, while the sum is 28.
Adding to 11343422134 its reverse (43122434311), we get a palindrome (54465856445).
The spelling of 11343422134 in words is "eleven billion, three hundred forty-three million, four hundred twenty-two thousand, one hundred thirty-four".
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