Base | Representation |
---|---|
bin | 11001110010101011111101… |
… | …100011111101100111000000 |
3 | 112212122012212012210222100122 |
4 | 121302223331203331213000 |
5 | 104332002012112203100 |
6 | 1041131003324235412 |
7 | 32615234462034416 |
oct | 3162537543754700 |
9 | 485565765728318 |
10 | 113434340350400 |
11 | 3316426299a843 |
12 | 1088040309bb68 |
13 | 4b3aa73ab1154 |
14 | 2002373a732b6 |
15 | d1aa4a52d985 |
hex | 672afd8fd9c0 |
113434340350400 has 168 divisors, whose sum is σ = 294887678569920. Its totient is φ = 42877014691840.
The previous prime is 113434340350381. The next prime is 113434340350403. The reversal of 113434340350400 is 4053043434311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113434340350403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23826707 + ... + 28188306.
Almost surely, 2113434340350400 is an apocalyptic number.
113434340350400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113434340350400 is an abundant number, since it is smaller than the sum of its proper divisors (181453338219520).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113434340350400 is a wasteful number, since it uses less digits than its factorization.
113434340350400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52015111 (or 52015096 counting only the distinct ones).
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 113434340350400 its reverse (4053043434311), we get a palindrome (117487383784711).
The spelling of 113434340350400 in words is "one hundred thirteen trillion, four hundred thirty-four billion, three hundred forty million, three hundred fifty thousand, four hundred".
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