113438131181 has 2 divisors, whose sum is σ = 113438131182. Its totient is φ = 113438131180.

The previous prime is 113438131129. The next prime is 113438131189. The reversal of 113438131181 is 181131834311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113414032900 + 24098281 = 336770^2 + 4909^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113438131181 is a prime.

It is a super-2 number, since 2×113438131181² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113438131189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56719065590 + 56719065591.

It is an arithmetic number, because the mean of its divisors is an integer number (56719065591).

Almost surely, 2^113438131181 is an apocalyptic number.

It is an amenable number.

113438131181 is a deficient number, since it is larger than the sum of its proper divisors (1).

113438131181 is an equidigital number, since it uses as much as digits as its factorization.

113438131181 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 35.

Adding to 113438131181 its reverse (181131834311), we get a palindrome (294569965492).

The spelling of 113438131181 in words is "one hundred thirteen billion, four hundred thirty-eight million, one hundred thirty-one thousand, one hundred eighty-one".