11344013 has 2 divisors, whose sum is σ = 11344014. Its totient is φ = 11344012.

The previous prime is 11344009. The next prime is 11344027. The reversal of 11344013 is 31044311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10738729 + 605284 = 3277^2 + 778^2 .

It is an emirp because it is prime and its reverse (31044311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11344013 - 2² = 11344009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11343982 and 11344000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11344043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672006 + 5672007.

It is an arithmetic number, because the mean of its divisors is an integer number (5672007).

Almost surely, 2^11344013 is an apocalyptic number.

It is an amenable number.

11344013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11344013 is an equidigital number, since it uses as much as digits as its factorization.

11344013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 11344013 is about 3368.0874394825. The cubic root of 11344013 is about 224.6926701179.

Adding to 11344013 its reverse (31044311), we get a palindrome (42388324).

The spelling of 11344013 in words is "eleven million, three hundred forty-four thousand, thirteen".