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11344013129 is a prime number
BaseRepresentation
bin10101001000010011…
…11110011101001001
31002021120202120112102
422210021332131021
5141213031410004
65113353323145
7551054343401
oct124411763511
932246676472
1011344013129
1148a1443a69
1222471064b5
1310ba295807
1479885d801
15465d9411e
hex2a427e749

11344013129 has 2 divisors, whose sum is σ = 11344013130. Its totient is φ = 11344013128.

The previous prime is 11344013111. The next prime is 11344013171. The reversal of 11344013129 is 92131044311.

It is a happy number.

11344013129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10717011529 + 627001600 = 103523^2 + 25040^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11344013129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11344013189) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672006564 + 5672006565.

It is an arithmetic number, because the mean of its divisors is an integer number (5672006565).

Almost surely, 211344013129 is an apocalyptic number.

It is an amenable number.

11344013129 is a deficient number, since it is larger than the sum of its proper divisors (1).

11344013129 is an equidigital number, since it uses as much as digits as its factorization.

11344013129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 11344013129 in words is "eleven billion, three hundred forty-four million, thirteen thousand, one hundred twenty-nine".