Base | Representation |
---|---|
bin | 10101001000010100… |
… | …00001000111011111 |
3 | 1002021120210010111012 |
4 | 22210022001013133 |
5 | 141213032232111 |
6 | 5113353445435 |
7 | 551054420234 |
oct | 124412010737 |
9 | 32246703435 |
10 | 11344024031 |
11 | 48a145117a |
12 | 224711087b |
13 | 10ba29a772 |
14 | 79886378b |
15 | 465d9748b |
hex | 2a42811df |
11344024031 has 2 divisors, whose sum is σ = 11344024032. Its totient is φ = 11344024030.
The previous prime is 11344024019. The next prime is 11344024057. The reversal of 11344024031 is 13042044311.
It is a weak prime.
It is an emirp because it is prime and its reverse (13042044311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11344024031 - 222 = 11339829727 is a prime.
It is a super-2 number, since 2×113440240312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11344023988 and 11344024006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11344024001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672012015 + 5672012016.
It is an arithmetic number, because the mean of its divisors is an integer number (5672012016).
Almost surely, 211344024031 is an apocalyptic number.
11344024031 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344024031 is an equidigital number, since it uses as much as digits as its factorization.
11344024031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 11344024031 its reverse (13042044311), we get a palindrome (24386068342).
The spelling of 11344024031 in words is "eleven billion, three hundred forty-four million, twenty-four thousand, thirty-one".
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