Base | Representation |
---|---|
bin | 1010010100010101010011… |
… | …1010000101010101111001 |
3 | 1111011111222001101010220121 |
4 | 2211011110322011111321 |
5 | 2441331344341003423 |
6 | 40043321033053241 |
7 | 2250415425445312 |
oct | 245052472052571 |
9 | 44144861333817 |
10 | 11344433141113 |
11 | 3684168839836 |
12 | 1332763857221 |
13 | 643a1089cb27 |
14 | 2b3105949609 |
15 | 14a164b3345d |
hex | a5154e85579 |
11344433141113 has 2 divisors, whose sum is σ = 11344433141114. Its totient is φ = 11344433141112.
The previous prime is 11344433141077. The next prime is 11344433141123. The reversal of 11344433141113 is 31114133444311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6744450552064 + 4599982589049 = 2597008^2 + 2144757^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11344433141113 is a prime.
It is not a weakly prime, because it can be changed into another prime (11344433141123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672216570556 + 5672216570557.
It is an arithmetic number, because the mean of its divisors is an integer number (5672216570557).
Almost surely, 211344433141113 is an apocalyptic number.
It is an amenable number.
11344433141113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11344433141113 is an equidigital number, since it uses as much as digits as its factorization.
11344433141113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20736, while the sum is 34.
Adding to 11344433141113 its reverse (31114133444311), we get a palindrome (42458566585424).
The spelling of 11344433141113 in words is "eleven trillion, three hundred forty-four billion, four hundred thirty-three million, one hundred forty-one thousand, one hundred thirteen".
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