Base | Representation |
---|---|
bin | 1010010100010111111010… |
… | …0001110001001101001011 |
3 | 1111011120202201021220002112 |
4 | 2211011332201301031023 |
5 | 2441334312120112001 |
6 | 40043514215252535 |
7 | 2250441634600352 |
oct | 245057641611513 |
9 | 44146681256075 |
10 | 11345131410251 |
11 | 3684496a06771 |
12 | 133291967a14b |
13 | 643ac2454432 |
14 | 2b3170592999 |
15 | 14a1a60b2cbb |
hex | a517e87134b |
11345131410251 has 2 divisors, whose sum is σ = 11345131410252. Its totient is φ = 11345131410250.
The previous prime is 11345131410233. The next prime is 11345131410317. The reversal of 11345131410251 is 15201413154311.
11345131410251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11345131410251 - 214 = 11345131393867 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11345133410251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672565705125 + 5672565705126.
It is an arithmetic number, because the mean of its divisors is an integer number (5672565705126).
Almost surely, 211345131410251 is an apocalyptic number.
11345131410251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11345131410251 is an equidigital number, since it uses as much as digits as its factorization.
11345131410251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 11345131410251 its reverse (15201413154311), we get a palindrome (26546544564562).
The spelling of 11345131410251 in words is "eleven trillion, three hundred forty-five billion, one hundred thirty-one million, four hundred ten thousand, two hundred fifty-one".
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