Base | Representation |
---|---|
bin | 10101001000011101… |
… | …00011000010001101 |
3 | 1002021200000110102202 |
4 | 22210032203002031 |
5 | 141213333232113 |
6 | 5113435131245 |
7 | 551100464315 |
oct | 124416430215 |
9 | 32250013382 |
10 | 11345211533 |
11 | 48a2092387 |
12 | 22475a3b25 |
13 | 10ba5c5126 |
14 | 798a92445 |
15 | 46602e258 |
hex | 2a43a308d |
11345211533 has 2 divisors, whose sum is σ = 11345211534. Its totient is φ = 11345211532.
The previous prime is 11345211529. The next prime is 11345211551. The reversal of 11345211533 is 33511254311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10439321929 + 905889604 = 102173^2 + 30098^2 .
It is a cyclic number.
It is not a de Polignac number, because 11345211533 - 22 = 11345211529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11345211496 and 11345211505.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11345210533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5672605766 + 5672605767.
It is an arithmetic number, because the mean of its divisors is an integer number (5672605767).
Almost surely, 211345211533 is an apocalyptic number.
It is an amenable number.
11345211533 is a deficient number, since it is larger than the sum of its proper divisors (1).
11345211533 is an equidigital number, since it uses as much as digits as its factorization.
11345211533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
Adding to 11345211533 its reverse (33511254311), we get a palindrome (44856465844).
The spelling of 11345211533 in words is "eleven billion, three hundred forty-five million, two hundred eleven thousand, five hundred thirty-three".
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