113500306453 has 2 divisors, whose sum is σ = 113500306454. Its totient is φ = 113500306452.

The previous prime is 113500306433. The next prime is 113500306457. The reversal of 113500306453 is 354603005311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100721812689 + 12778493764 = 317367^2 + 113042^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113500306453 is a prime.

It is a super-3 number, since 3×113500306453³ (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113500306457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56750153226 + 56750153227.

It is an arithmetic number, because the mean of its divisors is an integer number (56750153227).

Almost surely, 2^113500306453 is an apocalyptic number.

It is an amenable number.

113500306453 is a deficient number, since it is larger than the sum of its proper divisors (1).

113500306453 is an equidigital number, since it uses as much as digits as its factorization.

113500306453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 31.

The spelling of 113500306453 in words is "one hundred thirteen billion, five hundred million, three hundred six thousand, four hundred fifty-three".