Base | Representation |
---|---|
bin | 110100110110100100… |
… | …1010110010111001100 |
3 | 101211222000212111210100 |
4 | 1221231021112113030 |
5 | 3324422040122012 |
6 | 124050305411100 |
7 | 11125433530446 |
oct | 1515511262714 |
9 | 354860774710 |
10 | 113500317132 |
11 | 44153a74194 |
12 | 19bb7039a90 |
13 | a91a747987 |
14 | 56ca025496 |
15 | 2e445688dc |
hex | 1a6d2565cc |
113500317132 has 36 divisors (see below), whose sum is σ = 288663739000. Its totient is φ = 37601330112.
The previous prime is 113500317121. The next prime is 113500317149. The reversal of 113500317132 is 231713005311.
It is a happy number.
113500317132 is a `hidden beast` number, since 1 + 13 + 500 + 3 + 17 + 132 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a junction number, because it is equal to n+sod(n) for n = 113500317096 and 113500317105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9665257 + ... + 9676992.
Almost surely, 2113500317132 is an apocalyptic number.
113500317132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113500317132 is an abundant number, since it is smaller than the sum of its proper divisors (175163421868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113500317132 is a wasteful number, since it uses less digits than its factorization.
113500317132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19342422 (or 19342417 counting only the distinct ones).
The product of its (nonzero) digits is 1890, while the sum is 27.
The spelling of 113500317132 in words is "one hundred thirteen billion, five hundred million, three hundred seventeen thousand, one hundred thirty-two".
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