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11350219333 is a prime number
BaseRepresentation
bin10101001001000011…
…01001101001000101
31002022000102212211211
422210201221221011
5141221124004313
65114134331421
7551161162315
oct124441515105
932260385754
1011350219333
1148a49a2862
1222491b9b71
1310bb65961b
147995d7445
154666bce3d
hex2a4869a45

11350219333 has 2 divisors, whose sum is σ = 11350219334. Its totient is φ = 11350219332.

The previous prime is 11350219319. The next prime is 11350219343. The reversal of 11350219333 is 33391205311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8067273124 + 3282946209 = 89818^2 + 57297^2 .

It is an emirp because it is prime and its reverse (33391205311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11350219333 - 25 = 11350219301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11350219295 and 11350219304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11350219313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5675109666 + 5675109667.

It is an arithmetic number, because the mean of its divisors is an integer number (5675109667).

Almost surely, 211350219333 is an apocalyptic number.

It is an amenable number.

11350219333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11350219333 is an equidigital number, since it uses as much as digits as its factorization.

11350219333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7290, while the sum is 31.

The spelling of 11350219333 in words is "eleven billion, three hundred fifty million, two hundred nineteen thousand, three hundred thirty-three".