Base | Representation |
---|---|
bin | 110100110110101100… |
… | …0111011100000100001 |
3 | 101211222022120000102001 |
4 | 1221231120323200201 |
5 | 3324424111321231 |
6 | 124050533124001 |
7 | 11125513331164 |
oct | 1515530734041 |
9 | 354868500361 |
10 | 113504401441 |
11 | 44156303852 |
12 | 19bb8489601 |
13 | a91b547a22 |
14 | 56ca7a9adb |
15 | 2e44ac3b61 |
hex | 1a6d63b821 |
113504401441 has 2 divisors, whose sum is σ = 113504401442. Its totient is φ = 113504401440.
The previous prime is 113504401429. The next prime is 113504401469. The reversal of 113504401441 is 144104405311.
It is an a-pointer prime, because the next prime (113504401469) can be obtained adding 113504401441 to its sum of digits (28).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65938536225 + 47565865216 = 256785^2 + 218096^2 .
It is a cyclic number.
It is not a de Polignac number, because 113504401441 - 233 = 104914466849 is a prime.
It is not a weakly prime, because it can be changed into another prime (113504408441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56752200720 + 56752200721.
It is an arithmetic number, because the mean of its divisors is an integer number (56752200721).
Almost surely, 2113504401441 is an apocalyptic number.
It is an amenable number.
113504401441 is a deficient number, since it is larger than the sum of its proper divisors (1).
113504401441 is an equidigital number, since it uses as much as digits as its factorization.
113504401441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 113504401441 its reverse (144104405311), we get a palindrome (257608806752).
The spelling of 113504401441 in words is "one hundred thirteen billion, five hundred four million, four hundred one thousand, four hundred forty-one".
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