113514101 has 2 divisors, whose sum is σ = 113514102. Its totient is φ = 113514100.

The previous prime is 113514061. The next prime is 113514139. The reversal of 113514101 is 101415311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60078001 + 53436100 = 7751^2 + 7310^2 .

It is an emirp because it is prime and its reverse (101415311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113514101 - 2²² = 109319797 is a prime.

It is a super-2 number, since 2×113514101² = 25770902251676402, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113514101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113514601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56757050 + 56757051.

It is an arithmetic number, because the mean of its divisors is an integer number (56757051).

Almost surely, 2^113514101 is an apocalyptic number.

It is an amenable number.

113514101 is a deficient number, since it is larger than the sum of its proper divisors (1).

113514101 is an equidigital number, since it uses as much as digits as its factorization.

113514101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 113514101 is about 10654.2996484987. The cubic root of 113514101 is about 484.1908796208.

Adding to 113514101 its reverse (101415311), we get a palindrome (214929412).

The spelling of 113514101 in words is "one hundred thirteen million, five hundred fourteen thousand, one hundred one".