113525119 has 2 divisors, whose sum is σ = 113525120. Its totient is φ = 113525118.

The previous prime is 113525089. The next prime is 113525123. The reversal of 113525119 is 911525311.

It is a strong prime.

It is an emirp because it is prime and its reverse (911525311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113525119 - 2²³ = 105136511 is a prime.

It is a super-2 number, since 2×113525119² = 25775905287928322, which contains 22 as substring.

It is a Chen prime.

It is equal to p_6493411 and since 113525119 and 6493411 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113525129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56762559 + 56762560.

It is an arithmetic number, because the mean of its divisors is an integer number (56762560).

Almost surely, 2^113525119 is an apocalyptic number.

113525119 is a deficient number, since it is larger than the sum of its proper divisors (1).

113525119 is an equidigital number, since it uses as much as digits as its factorization.

113525119 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1350, while the sum is 28.

The square root of 113525119 is about 10654.8167041953. The cubic root of 113525119 is about 484.2065447599.

It can be divided in two parts, 11352 and 5119, that added together give a triangular number (16471 = T₁₈₁).

The spelling of 113525119 in words is "one hundred thirteen million, five hundred twenty-five thousand, one hundred nineteen".