Base | Representation |
---|---|
bin | 1010010100110011110000… |
… | …1001011010101000000111 |
3 | 1111012022001202011222002111 |
4 | 2211030330021122220013 |
5 | 2442000120030232042 |
6 | 40051152125321451 |
7 | 2251125125654404 |
oct | 245147411325007 |
9 | 44168052158074 |
10 | 11352607664647 |
11 | 3687683079307 |
12 | 1334265406287 |
13 | 64471431a1c2 |
14 | 2b367d4832ab |
15 | 14a492604517 |
hex | a533c25aa07 |
11352607664647 has 2 divisors, whose sum is σ = 11352607664648. Its totient is φ = 11352607664646.
The previous prime is 11352607664633. The next prime is 11352607664683. The reversal of 11352607664647 is 74646670625311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11352607664647 - 219 = 11352607140359 is a prime.
It is a super-2 number, since 2×113526076646472 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11352607664591 and 11352607664600.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11352607674647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5676303832323 + 5676303832324.
It is an arithmetic number, because the mean of its divisors is an integer number (5676303832324).
Almost surely, 211352607664647 is an apocalyptic number.
11352607664647 is a deficient number, since it is larger than the sum of its proper divisors (1).
11352607664647 is an equidigital number, since it uses as much as digits as its factorization.
11352607664647 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30481920, while the sum is 58.
The spelling of 11352607664647 in words is "eleven trillion, three hundred fifty-two billion, six hundred seven million, six hundred sixty-four thousand, six hundred forty-seven".
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