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1135302343451 is a prime number
BaseRepresentation
bin10000100001010101010…
…010101111101100011011
311000112102011122121220122
4100201111102233230123
5122100044344442301
62225314541143455
7145010564460443
oct20412522575433
94015364577818
101135302343451
113a852a637151
1216404255ab8b
138309b83a5b3
143cd3dbd7123
151e7e9d5481b
hex108554afb1b

1135302343451 has 2 divisors, whose sum is σ = 1135302343452. Its totient is φ = 1135302343450.

The previous prime is 1135302343393. The next prime is 1135302343453. The reversal of 1135302343451 is 1543432035311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1543432035311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1135302343451 is a prime.

It is a super-2 number, since 2×11353023434512 (a number of 25 digits) contains 22 as substring.

Together with 1135302343453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1135302343453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567651171725 + 567651171726.

It is an arithmetic number, because the mean of its divisors is an integer number (567651171726).

Almost surely, 21135302343451 is an apocalyptic number.

1135302343451 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135302343451 is an equidigital number, since it uses as much as digits as its factorization.

1135302343451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1135302343451 its reverse (1543432035311), we get a palindrome (2678734378762).

The spelling of 1135302343451 in words is "one trillion, one hundred thirty-five billion, three hundred two million, three hundred forty-three thousand, four hundred fifty-one".