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11353123539997 is a prime number
BaseRepresentation
bin1010010100110101101011…
…1001010100110000011101
31111012100101200220011000221
42211031122321110300131
52442002144111234442
640051315234321341
72251143661561231
oct245153271246035
944170350804027
1011353123539997
113687918299078
12133438a129251
136447971701a5
142b36cbbac5c1
1514a4c2a56467
hexa535ae54c1d

11353123539997 has 2 divisors, whose sum is σ = 11353123539998. Its totient is φ = 11353123539996.

The previous prime is 11353123539983. The next prime is 11353123540001. The reversal of 11353123539997 is 79993532135311.

11353123539997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6658768650681 + 4694354889316 = 2580459^2 + 2166646^2 .

It is a cyclic number.

It is not a de Polignac number, because 11353123539997 - 235 = 11318763801629 is a prime.

It is a super-2 number, since 2×113531235399972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11353123539977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5676561769998 + 5676561769999.

It is an arithmetic number, because the mean of its divisors is an integer number (5676561769999).

Almost surely, 211353123539997 is an apocalyptic number.

It is an amenable number.

11353123539997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11353123539997 is an equidigital number, since it uses as much as digits as its factorization.

11353123539997 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20667150, while the sum is 61.

The spelling of 11353123539997 in words is "eleven trillion, three hundred fifty-three billion, one hundred twenty-three million, five hundred thirty-nine thousand, nine hundred ninety-seven".