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113534044440133 is a prime number
BaseRepresentation
bin11001110100001000110100…
…011000111000011001000101
3112212222202012202122112000211
4121310020310120320121011
5104340120210334041013
61041244453041035421
732625364313565652
oct3164106430703105
9485882182575024
10113534044440133
11331a25772950a9
12108977a9925b71
134b472a31c5455
1420071116a6c29
15d1d4337b623d
hex674234638645

113534044440133 has 2 divisors, whose sum is σ = 113534044440134. Its totient is φ = 113534044440132.

The previous prime is 113534044440083. The next prime is 113534044440139. The reversal of 113534044440133 is 331044440435311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103078088896644 + 10455955543489 = 10152738^2 + 3233567^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113534044440133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113534044440139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767022220066 + 56767022220067.

It is an arithmetic number, because the mean of its divisors is an integer number (56767022220067).

Almost surely, 2113534044440133 is an apocalyptic number.

It is an amenable number.

113534044440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

113534044440133 is an equidigital number, since it uses as much as digits as its factorization.

113534044440133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 113534044440133 its reverse (331044440435311), we get a palindrome (444578484875444).

The spelling of 113534044440133 in words is "one hundred thirteen trillion, five hundred thirty-four billion, forty-four million, four hundred forty thousand, one hundred thirty-three".