Base | Representation |
---|---|
bin | 11001110100001001011110… |
… | …010011010101001000100011 |
3 | 112212222211000202211011112101 |
4 | 121310021132103111020203 |
5 | 104340123130343044232 |
6 | 1041245050520511231 |
7 | 32625420612565363 |
oct | 3164113623251043 |
9 | 485884022734471 |
10 | 113534747628067 |
11 | 331a28a8211657 |
12 | 1089796531b517 |
13 | 4b47385aac89c |
14 | 200717ac309a3 |
15 | d1d4753b81e7 |
hex | 67425e4d5223 |
113534747628067 has 2 divisors, whose sum is σ = 113534747628068. Its totient is φ = 113534747628066.
The previous prime is 113534747627879. The next prime is 113534747628077. The reversal of 113534747628067 is 760826747435311.
It is a strong prime.
It is an emirp because it is prime and its reverse (760826747435311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113534747628067 is a prime.
It is not a weakly prime, because it can be changed into another prime (113534747628077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767373814033 + 56767373814034.
It is an arithmetic number, because the mean of its divisors is an integer number (56767373814034).
Almost surely, 2113534747628067 is an apocalyptic number.
113534747628067 is a deficient number, since it is larger than the sum of its proper divisors (1).
113534747628067 is an equidigital number, since it uses as much as digits as its factorization.
113534747628067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 142248960, while the sum is 64.
The spelling of 113534747628067 in words is "one hundred thirteen trillion, five hundred thirty-four billion, seven hundred forty-seven million, six hundred twenty-eight thousand, sixty-seven".
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