Base | Representation |
---|---|
bin | 11001110100001001101101… |
… | …011111001101011100011011 |
3 | 112212222211200112012221122212 |
4 | 121310021231133031130123 |
5 | 104340124141103304124 |
6 | 1041245132101305335 |
7 | 32625430125245306 |
oct | 3164115537153433 |
9 | 485884615187585 |
10 | 113535002400539 |
11 | 331a2a19004a15 |
12 | 10897a1670524b |
13 | 4b473c6803625 |
14 | 20071a29cdb3d |
15 | d1d48c94140e |
hex | 67426d7cd71b |
113535002400539 has 2 divisors, whose sum is σ = 113535002400540. Its totient is φ = 113535002400538.
The previous prime is 113535002400503. The next prime is 113535002400553. The reversal of 113535002400539 is 935004200535311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113535002400539 - 28 = 113535002400283 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113535002400496 and 113535002400505.
It is not a weakly prime, because it can be changed into another prime (113535002409539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767501200269 + 56767501200270.
It is an arithmetic number, because the mean of its divisors is an integer number (56767501200270).
Almost surely, 2113535002400539 is an apocalyptic number.
113535002400539 is a deficient number, since it is larger than the sum of its proper divisors (1).
113535002400539 is an equidigital number, since it uses as much as digits as its factorization.
113535002400539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243000, while the sum is 41.
The spelling of 113535002400539 in words is "one hundred thirteen trillion, five hundred thirty-five billion, two million, four hundred thousand, five hundred thirty-nine".
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