Search a number
-
+
113535002400553 is a prime number
BaseRepresentation
bin11001110100001001101101…
…011111001101011100101001
3112212222211200112012221200101
4121310021231133031130221
5104340124141103304203
61041245132101305401
732625430125245326
oct3164115537153451
9485884615187611
10113535002400553
11331a2a19004a28
1210897a16705261
134b473c6803636
1420071a29cdb4d
15d1d48c94141d
hex67426d7cd729

113535002400553 has 2 divisors, whose sum is σ = 113535002400554. Its totient is φ = 113535002400552.

The previous prime is 113535002400539. The next prime is 113535002400571. The reversal of 113535002400553 is 355004200535311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86759314123024 + 26775688277529 = 9314468^2 + 5174523^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113535002400553 is a prime.

It is not a weakly prime, because it can be changed into another prime (113535002400503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767501200276 + 56767501200277.

It is an arithmetic number, because the mean of its divisors is an integer number (56767501200277).

Almost surely, 2113535002400553 is an apocalyptic number.

It is an amenable number.

113535002400553 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535002400553 is an equidigital number, since it uses as much as digits as its factorization.

113535002400553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 113535002400553 its reverse (355004200535311), we get a palindrome (468539202935864).

The spelling of 113535002400553 in words is "one hundred thirteen trillion, five hundred thirty-five billion, two million, four hundred thousand, five hundred fifty-three".