Search a number
-
+
113535521334343 is a prime number
BaseRepresentation
bin11001110100001010001100…
…011010110010010001000111
3112212222220000200200112000101
4121310022030122302101013
5104340131221430144333
61041245255400024531
732625446026150663
oct3164121432622107
9485886020615011
10113535521334343
11331a3164a23629
1210897b40462147
134b4747a187754
1420072118b38a3
15d1d4bd29967d
hex67428c6b2447

113535521334343 has 2 divisors, whose sum is σ = 113535521334344. Its totient is φ = 113535521334342.

The previous prime is 113535521334233. The next prime is 113535521334353. The reversal of 113535521334343 is 343433125535311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113535521334343 - 29 = 113535521333831 is a prime.

It is a super-2 number, since 2×1135355213343432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113535521334293 and 113535521334302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113535521334353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767760667171 + 56767760667172.

It is an arithmetic number, because the mean of its divisors is an integer number (56767760667172).

Almost surely, 2113535521334343 is an apocalyptic number.

113535521334343 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535521334343 is an equidigital number, since it uses as much as digits as its factorization.

113535521334343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2916000, while the sum is 46.

Adding to 113535521334343 its reverse (343433125535311), we get a palindrome (456968646869654).

The spelling of 113535521334343 in words is "one hundred thirteen trillion, five hundred thirty-five billion, five hundred twenty-one million, three hundred thirty-four thousand, three hundred forty-three".