Search a number
-
+
11354040149401 is a prime number
BaseRepresentation
bin1010010100111001000110…
…0001111010010110011001
31111012102202120122201202101
42211032101201322112121
52442011033234240101
640051550220403401
72251205461614655
oct245162141722631
944172676581671
1011354040149401
113688248735304
1213345a50a6561
136448b2030911
142b377780da65
1514a528264401
hexa539187a599

11354040149401 has 2 divisors, whose sum is σ = 11354040149402. Its totient is φ = 11354040149400.

The previous prime is 11354040149399. The next prime is 11354040149479. The reversal of 11354040149401 is 10494104045311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5916277875600 + 5437762273801 = 2432340^2 + 2331901^2 .

It is an emirp because it is prime and its reverse (10494104045311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11354040149401 - 21 = 11354040149399 is a prime.

Together with 11354040149399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11354040149701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677020074700 + 5677020074701.

It is an arithmetic number, because the mean of its divisors is an integer number (5677020074701).

Almost surely, 211354040149401 is an apocalyptic number.

It is an amenable number.

11354040149401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11354040149401 is an equidigital number, since it uses as much as digits as its factorization.

11354040149401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34560, while the sum is 37.

The spelling of 11354040149401 in words is "eleven trillion, three hundred fifty-four billion, forty million, one hundred forty-nine thousand, four hundred one".