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11354131 is a prime number
BaseRepresentation
bin101011010100…
…000000010011
3210100211221101
4223110000103
510401313011
61043205231
7165336265
oct53240023
923324841
1011354131
116455588
123976817
132477029
141717b35
15ee42c1
hexad4013

11354131 has 2 divisors, whose sum is σ = 11354132. Its totient is φ = 11354130.

The previous prime is 11354129. The next prime is 11354159. The reversal of 11354131 is 13145311.

It is a weak prime.

It is an emirp because it is prime and its reverse (13145311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11354131 - 21 = 11354129 is a prime.

It is a super-2 number, since 2×113541312 = 257832581530322, which contains 22 as substring.

Together with 11354129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11354099 and 11354108.

It is not a weakly prime, because it can be changed into another prime (11357131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677065 + 5677066.

It is an arithmetic number, because the mean of its divisors is an integer number (5677066).

Almost surely, 211354131 is an apocalyptic number.

11354131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11354131 is an equidigital number, since it uses as much as digits as its factorization.

11354131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 180, while the sum is 19.

The square root of 11354131 is about 3369.5891440946. The cubic root of 11354131 is about 224.7594532119.

Adding to 11354131 its reverse (13145311), we get a palindrome (24499442).

The spelling of 11354131 in words is "eleven million, three hundred fifty-four thousand, one hundred thirty-one".