Base | Representation |
---|---|
bin | 10000100001011100010… |
… | …011101110001100011111 |
3 | 11000112201101010020011212 |
4 | 100201130103232030133 |
5 | 122100320012234332 |
6 | 2225334343535035 |
7 | 145013524046123 |
oct | 20413423561437 |
9 | 4015641106155 |
10 | 1135420039967 |
11 | 3a85900152a4 |
12 | 164075a5a47b |
13 | 830ba038bc5 |
14 | 3cd516b3583 |
15 | 1e8053528b2 |
hex | 1085c4ee31f |
1135420039967 has 2 divisors, whose sum is σ = 1135420039968. Its totient is φ = 1135420039966.
The previous prime is 1135420039961. The next prime is 1135420040011. The reversal of 1135420039967 is 7699300245311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1135420039967 - 214 = 1135420023583 is a prime.
It is a super-2 number, since 2×11354200399672 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135420039961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567710019983 + 567710019984.
It is an arithmetic number, because the mean of its divisors is an integer number (567710019984).
Almost surely, 21135420039967 is an apocalyptic number.
1135420039967 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135420039967 is an equidigital number, since it uses as much as digits as its factorization.
1135420039967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 50.
The spelling of 1135420039967 in words is "one trillion, one hundred thirty-five billion, four hundred twenty million, thirty-nine thousand, nine hundred sixty-seven".
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