Base | Representation |
---|---|
bin | 10000100001011100011… |
… | …010001110000001011111 |
3 | 11000112201111022202120112 |
4 | 100201130122032001133 |
5 | 122100320431240244 |
6 | 2225334444240235 |
7 | 145013544401612 |
oct | 20413432160137 |
9 | 4015644282515 |
10 | 1135421743199 |
11 | 3a8590a78a27 |
12 | 16407654007b |
13 | 830ba4b4233 |
14 | 3cd519d8179 |
15 | 1e80558c39e |
hex | 1085c68e05f |
1135421743199 has 2 divisors, whose sum is σ = 1135421743200. Its totient is φ = 1135421743198.
The previous prime is 1135421743153. The next prime is 1135421743271. The reversal of 1135421743199 is 9913471245311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1135421743199 is a prime.
It is a super-3 number, since 3×11354217431993 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135421743499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567710871599 + 567710871600.
It is an arithmetic number, because the mean of its divisors is an integer number (567710871600).
Almost surely, 21135421743199 is an apocalyptic number.
1135421743199 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135421743199 is an equidigital number, since it uses as much as digits as its factorization.
1135421743199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 816480, while the sum is 50.
The spelling of 1135421743199 in words is "one trillion, one hundred thirty-five billion, four hundred twenty-one million, seven hundred forty-three thousand, one hundred ninety-nine".
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