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113542214503 is a prime number
BaseRepresentation
bin110100110111110100…
…1001011001101100111
3101212001221201010011211
41221233221023031213
53330013301331003
6124054403412251
711126452620304
oct1515751131547
9355057633154
10113542214503
1144175690313
121a009084087
13a926327013
1456d18100ab
152e4809296d
hex1a6fa4b367

113542214503 has 2 divisors, whose sum is σ = 113542214504. Its totient is φ = 113542214502.

The previous prime is 113542214479. The next prime is 113542214507. The reversal of 113542214503 is 305412245311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113542214503 - 213 = 113542206311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113542214507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771107251 + 56771107252.

It is an arithmetic number, because the mean of its divisors is an integer number (56771107252).

Almost surely, 2113542214503 is an apocalyptic number.

113542214503 is a deficient number, since it is larger than the sum of its proper divisors (1).

113542214503 is an equidigital number, since it uses as much as digits as its factorization.

113542214503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 113542214503 its reverse (305412245311), we get a palindrome (418954459814).

The spelling of 113542214503 in words is "one hundred thirteen billion, five hundred forty-two million, two hundred fourteen thousand, five hundred three".