Base | Representation |
---|---|
bin | 110100110111110100… |
… | …1001011001101100111 |
3 | 101212001221201010011211 |
4 | 1221233221023031213 |
5 | 3330013301331003 |
6 | 124054403412251 |
7 | 11126452620304 |
oct | 1515751131547 |
9 | 355057633154 |
10 | 113542214503 |
11 | 44175690313 |
12 | 1a009084087 |
13 | a926327013 |
14 | 56d18100ab |
15 | 2e4809296d |
hex | 1a6fa4b367 |
113542214503 has 2 divisors, whose sum is σ = 113542214504. Its totient is φ = 113542214502.
The previous prime is 113542214479. The next prime is 113542214507. The reversal of 113542214503 is 305412245311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113542214503 - 213 = 113542206311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113542214507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56771107251 + 56771107252.
It is an arithmetic number, because the mean of its divisors is an integer number (56771107252).
Almost surely, 2113542214503 is an apocalyptic number.
113542214503 is a deficient number, since it is larger than the sum of its proper divisors (1).
113542214503 is an equidigital number, since it uses as much as digits as its factorization.
113542214503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 113542214503 its reverse (305412245311), we get a palindrome (418954459814).
The spelling of 113542214503 in words is "one hundred thirteen billion, five hundred forty-two million, two hundred fourteen thousand, five hundred three".
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