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11354244133 is a prime number
BaseRepresentation
bin10101001001100010…
…00000010000100101
31002022022000100211111
422210301000100211
5141223141303013
65114400505021
7551240324401
oct124461002045
932268010744
1011354244133
1148a71a1741
12224a61b171
1310bc43856b
14799d64101
15466c1573d
hex2a4c40425

11354244133 has 2 divisors, whose sum is σ = 11354244134. Its totient is φ = 11354244132.

The previous prime is 11354244107. The next prime is 11354244151. The reversal of 11354244133 is 33144245311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11334370369 + 19873764 = 106463^2 + 4458^2 .

It is a cyclic number.

It is not a de Polignac number, because 11354244133 - 213 = 11354235941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11354244095 and 11354244104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11354244163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677122066 + 5677122067.

It is an arithmetic number, because the mean of its divisors is an integer number (5677122067).

Almost surely, 211354244133 is an apocalyptic number.

It is an amenable number.

11354244133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11354244133 is an equidigital number, since it uses as much as digits as its factorization.

11354244133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 17280, while the sum is 31.

Adding to 11354244133 its reverse (33144245311), we get a palindrome (44498489444).

The spelling of 11354244133 in words is "eleven billion, three hundred fifty-four million, two hundred forty-four thousand, one hundred thirty-three".