Base | Representation |
---|---|
bin | 11001110100011000110011… |
… | …110001100110011110111011 |
3 | 112220001101112100020011021211 |
4 | 121310120303301212132323 |
5 | 104340410341241343342 |
6 | 1041300412500343551 |
7 | 32626542636544546 |
oct | 3164306361463673 |
9 | 486041470204254 |
10 | 113551214012347 |
11 | 331a9888043901 |
12 | 1089ab9b9a4bb7 |
13 | 4b48aab37b237 |
14 | 2007c9dac785d |
15 | d1dadacd6c17 |
hex | 674633c667bb |
113551214012347 has 2 divisors, whose sum is σ = 113551214012348. Its totient is φ = 113551214012346.
The previous prime is 113551214012311. The next prime is 113551214012381. The reversal of 113551214012347 is 743210412155311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113551214012347 - 215 = 113551213979579 is a prime.
It is not a weakly prime, because it can be changed into another prime (113551214012387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56775607006173 + 56775607006174.
It is an arithmetic number, because the mean of its divisors is an integer number (56775607006174).
Almost surely, 2113551214012347 is an apocalyptic number.
113551214012347 is a deficient number, since it is larger than the sum of its proper divisors (1).
113551214012347 is an equidigital number, since it uses as much as digits as its factorization.
113551214012347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 40.
Adding to 113551214012347 its reverse (743210412155311), we get a palindrome (856761626167658).
The spelling of 113551214012347 in words is "one hundred thirteen trillion, five hundred fifty-one billion, two hundred fourteen million, twelve thousand, three hundred forty-seven".
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