Base | Representation |
---|---|
bin | 11001110100011000110011… |
… | …110001100110011110010111 |
3 | 112220001101112100020011020111 |
4 | 121310120303301212132113 |
5 | 104340410341241343221 |
6 | 1041300412500343451 |
7 | 32626542636544465 |
oct | 3164306361463627 |
9 | 486041470204214 |
10 | 113551214012311 |
11 | 331a9888043879 |
12 | 1089ab9b9a4b87 |
13 | 4b48aab37b20a |
14 | 2007c9dac7835 |
15 | d1dadacd6be1 |
hex | 674633c66797 |
113551214012311 has 2 divisors, whose sum is σ = 113551214012312. Its totient is φ = 113551214012310.
The previous prime is 113551214012261. The next prime is 113551214012347. The reversal of 113551214012311 is 113210412155311.
It is a strong prime.
It is an emirp because it is prime and its reverse (113210412155311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113551214012311 - 213 = 113551214004119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113551214012381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56775607006155 + 56775607006156.
It is an arithmetic number, because the mean of its divisors is an integer number (56775607006156).
Almost surely, 2113551214012311 is an apocalyptic number.
113551214012311 is a deficient number, since it is larger than the sum of its proper divisors (1).
113551214012311 is an equidigital number, since it uses as much as digits as its factorization.
113551214012311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 31.
Adding to 113551214012311 its reverse (113210412155311), we get a palindrome (226761626167622).
The spelling of 113551214012311 in words is "one hundred thirteen trillion, five hundred fifty-one billion, two hundred fourteen million, twelve thousand, three hundred eleven".
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