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11355212241073 is a prime number
BaseRepresentation
bin1010010100111101011101…
…1001000101100010110001
31111012112210021011011021001
42211033113121011202301
52442020433313203243
640052302410402001
72251246513335601
oct245172731054261
944175707134231
1011355212241073
11368879a30a108
121334871730301
13644a3ab0319c
142b3849356c01
1514a5960daa4d
hexa53d76458b1

11355212241073 has 2 divisors, whose sum is σ = 11355212241074. Its totient is φ = 11355212241072.

The previous prime is 11355212241047. The next prime is 11355212241101. The reversal of 11355212241073 is 37014221255311.

11355212241073 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8369286992784 + 2985925248289 = 2892972^2 + 1727983^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11355212241073 is a prime.

It is not a weakly prime, because it can be changed into another prime (11355212241473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677606120536 + 5677606120537.

It is an arithmetic number, because the mean of its divisors is an integer number (5677606120537).

Almost surely, 211355212241073 is an apocalyptic number.

It is an amenable number.

11355212241073 is a deficient number, since it is larger than the sum of its proper divisors (1).

11355212241073 is an equidigital number, since it uses as much as digits as its factorization.

11355212241073 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 37.

Adding to 11355212241073 its reverse (37014221255311), we get a palindrome (48369433496384).

The spelling of 11355212241073 in words is "eleven trillion, three hundred fifty-five billion, two hundred twelve million, two hundred forty-one thousand, seventy-three".