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11355212241047 is a prime number
BaseRepresentation
bin1010010100111101011101…
…1001000101100010010111
31111012112210021011011020002
42211033113121011202113
52442020433313203142
640052302410401515
72251246513335533
oct245172731054227
944175707134202
1011355212241047
11368879a30a094
12133487173029b
13644a3ab0317c
142b3849356bc3
1514a5960daa32
hexa53d7645897

11355212241047 has 2 divisors, whose sum is σ = 11355212241048. Its totient is φ = 11355212241046.

The previous prime is 11355212240993. The next prime is 11355212241073. The reversal of 11355212241047 is 74014221255311.

It is a strong prime.

It is an emirp because it is prime and its reverse (74014221255311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11355212241047 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11355212241047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11355212241847) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5677606120523 + 5677606120524.

It is an arithmetic number, because the mean of its divisors is an integer number (5677606120524).

Almost surely, 211355212241047 is an apocalyptic number.

11355212241047 is a deficient number, since it is larger than the sum of its proper divisors (1).

11355212241047 is an equidigital number, since it uses as much as digits as its factorization.

11355212241047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 38.

Adding to 11355212241047 its reverse (74014221255311), we get a palindrome (85369433496358).

The spelling of 11355212241047 in words is "eleven trillion, three hundred fifty-five billion, two hundred twelve million, two hundred forty-one thousand, forty-seven".