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113552454340121 is a prime number
BaseRepresentation
bin11001110100011001111101…
…101101000100111000011001
3112220001111201210010100010112
4121310121331231010320121
5104340420411302340441
61041301135525054105
732626615450264526
oct3164317555047031
9486044653110115
10113552454340121
11331aa364194485
121089b287257335
134b48c483224b4
142007d7a71414d
15d1db5eb3b4eb
hex67467db44e19

113552454340121 has 2 divisors, whose sum is σ = 113552454340122. Its totient is φ = 113552454340120.

The previous prime is 113552454340081. The next prime is 113552454340123. The reversal of 113552454340121 is 121043454255311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113476587146521 + 75867193600 = 10652539^2 + 275440^2 .

It is a cyclic number.

It is not a de Polignac number, because 113552454340121 - 218 = 113552454077977 is a prime.

Together with 113552454340123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113552454340123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776227170060 + 56776227170061.

It is an arithmetic number, because the mean of its divisors is an integer number (56776227170061).

Almost surely, 2113552454340121 is an apocalyptic number.

It is an amenable number.

113552454340121 is a deficient number, since it is larger than the sum of its proper divisors (1).

113552454340121 is an equidigital number, since it uses as much as digits as its factorization.

113552454340121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 41.

The spelling of 113552454340121 in words is "one hundred thirteen trillion, five hundred fifty-two billion, four hundred fifty-four million, three hundred forty thousand, one hundred twenty-one".