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113552524331479 is a prime number
BaseRepresentation
bin11001110100011010000001…
…111000000100100111010111
3112220001111220122211021020001
4121310122001320010213113
5104340421032212101404
61041301150505152131
732626620260224132
oct3164320170044727
9486044818737201
10113552524331479
11331aa39a749a82
121089b2a678b647
134b48c5998a0bc
142007d85b33219
15d1db65d647a4
hex674681e049d7

113552524331479 has 2 divisors, whose sum is σ = 113552524331480. Its totient is φ = 113552524331478.

The previous prime is 113552524331471. The next prime is 113552524331501. The reversal of 113552524331479 is 974133425255311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113552524331479 - 23 = 113552524331471 is a prime.

It is a super-2 number, since 2×1135525243314792 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113552524331471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776262165739 + 56776262165740.

It is an arithmetic number, because the mean of its divisors is an integer number (56776262165740).

Almost surely, 2113552524331479 is an apocalyptic number.

113552524331479 is a deficient number, since it is larger than the sum of its proper divisors (1).

113552524331479 is an equidigital number, since it uses as much as digits as its factorization.

113552524331479 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13608000, while the sum is 55.

The spelling of 113552524331479 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred twenty-four million, three hundred thirty-one thousand, four hundred seventy-nine".