113552531504354 has 4 divisors (see below), whose sum is σ = 170328797256534. Its totient is φ = 56776265752176.

The previous prime is 113552531504353. The next prime is 113552531504407. The reversal of 113552531504354 is 453405135255311.

113552531504354 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 100793026022329 + 12759505482025 = 10039573^2 + 3572045^2 .

It is a super-2 number, since 2×113552531504354² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113552531504299 and 113552531504308.

It is not an unprimeable number, because it can be changed into a prime (113552531504351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28388132876087 + ... + 28388132876090.

Almost surely, 2^{113552531504354} is an apocalyptic number.

113552531504354 is a deficient number, since it is larger than the sum of its proper divisors (56776265752180).

113552531504354 is an equidigital number, since it uses as much as digits as its factorization.

113552531504354 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56776265752179.

The product of its (nonzero) digits is 2700000, while the sum is 47.

Adding to 113552531504354 its reverse (453405135255311), we get a palindrome (566957666759665).

The spelling of 113552531504354 in words is "one hundred thirteen trillion, five hundred fifty-two billion, five hundred thirty-one million, five hundred four thousand, three hundred fifty-four".