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1135531324481 is a prime number
BaseRepresentation
bin10000100001100010111…
…100001111010001000001
311000120000010112001211112
4100201202330033101001
5122101032004340411
62225353401053105
7145016345000561
oct20414274172101
94016003461745
101135531324481
113a8637913a74
121640a7187195
1383107100b28
143cd623a0da1
151e80eed5b8b
hex10862f0f441

1135531324481 has 2 divisors, whose sum is σ = 1135531324482. Its totient is φ = 1135531324480.

The previous prime is 1135531324439. The next prime is 1135531324541. The reversal of 1135531324481 is 1844231355311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1122839048881 + 12692275600 = 1059641^2 + 112660^2 .

It is an emirp because it is prime and its reverse (1844231355311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1135531324481 is a prime.

It is a super-2 number, since 2×11355313244812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1135531624481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567765662240 + 567765662241.

It is an arithmetic number, because the mean of its divisors is an integer number (567765662241).

Almost surely, 21135531324481 is an apocalyptic number.

It is an amenable number.

1135531324481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135531324481 is an equidigital number, since it uses as much as digits as its factorization.

1135531324481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 172800, while the sum is 41.

Adding to 1135531324481 its reverse (1844231355311), we get a palindrome (2979762679792).

The spelling of 1135531324481 in words is "one trillion, one hundred thirty-five billion, five hundred thirty-one million, three hundred twenty-four thousand, four hundred eighty-one".