Base | Representation |
---|---|
bin | 10000100001100010111… |
… | …100001111010001111101 |
3 | 11000120000010112001220202 |
4 | 100201202330033101331 |
5 | 122101032004341131 |
6 | 2225353401053245 |
7 | 145016345001005 |
oct | 20414274172175 |
9 | 4016003461822 |
10 | 1135531324541 |
11 | 3a8637914019 |
12 | 1640a7187225 |
13 | 83107100b73 |
14 | 3cd623a1005 |
15 | 1e80eed5bcb |
hex | 10862f0f47d |
1135531324541 has 2 divisors, whose sum is σ = 1135531324542. Its totient is φ = 1135531324540.
The previous prime is 1135531324481. The next prime is 1135531324567. The reversal of 1135531324541 is 1454231355311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 625372548025 + 510158776516 = 790805^2 + 714254^2 .
It is a cyclic number.
It is not a de Polignac number, because 1135531324541 - 218 = 1135531062397 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1135531324495 and 1135531324504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135531324141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567765662270 + 567765662271.
It is an arithmetic number, because the mean of its divisors is an integer number (567765662271).
Almost surely, 21135531324541 is an apocalyptic number.
It is an amenable number.
1135531324541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135531324541 is an equidigital number, since it uses as much as digits as its factorization.
1135531324541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108000, while the sum is 38.
Adding to 1135531324541 its reverse (1454231355311), we get a palindrome (2589762679852).
The spelling of 1135531324541 in words is "one trillion, one hundred thirty-five billion, five hundred thirty-one million, three hundred twenty-four thousand, five hundred forty-one".
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