Base | Representation |
---|---|
bin | 11001110100011010111001… |
… | …001111000011110000000001 |
3 | 112220001121022101110210210002 |
4 | 121310122321033003300001 |
5 | 104340424432443313004 |
6 | 1041301423004045345 |
7 | 32626652265530123 |
oct | 3164327117036001 |
9 | 486047271423702 |
10 | 113553453104129 |
11 | 331aa826a43685 |
12 | 1089b505833855 |
13 | 4b49077218c0c |
14 | 200803321d213 |
15 | d1dbbc67661e |
hex | 6746b93c3c01 |
113553453104129 has 2 divisors, whose sum is σ = 113553453104130. Its totient is φ = 113553453104128.
The previous prime is 113553453104101. The next prime is 113553453104227. The reversal of 113553453104129 is 921401354355311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105892332160000 + 7661120944129 = 10290400^2 + 2767873^2 .
It is a cyclic number.
It is not a de Polignac number, because 113553453104129 - 28 = 113553453103873 is a prime.
It is a super-3 number, since 3×1135534531041293 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (113553453304129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776726552064 + 56776726552065.
It is an arithmetic number, because the mean of its divisors is an integer number (56776726552065).
Almost surely, 2113553453104129 is an apocalyptic number.
It is an amenable number.
113553453104129 is a deficient number, since it is larger than the sum of its proper divisors (1).
113553453104129 is an equidigital number, since it uses as much as digits as its factorization.
113553453104129 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 47.
The spelling of 113553453104129 in words is "one hundred thirteen trillion, five hundred fifty-three billion, four hundred fifty-three million, one hundred four thousand, one hundred twenty-nine".
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