Base | Representation |
---|---|
bin | 10000100001100011001… |
… | …011101011001110101101 |
3 | 11000120000102010122212022 |
4 | 100201203023223032231 |
5 | 122101034023334211 |
6 | 2225354023515525 |
7 | 145016424253541 |
oct | 20414313531655 |
9 | 4016012118768 |
10 | 1135535371181 |
11 | 3a863a128352 |
12 | 1640a85b8ba5 |
13 | 83107bb9a23 |
14 | 3cd62b35a21 |
15 | 1e810534bdb |
hex | 108632eb3ad |
1135535371181 has 2 divisors, whose sum is σ = 1135535371182. Its totient is φ = 1135535371180.
The previous prime is 1135535371121. The next prime is 1135535371189. The reversal of 1135535371181 is 1811735355311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 831134895556 + 304400475625 = 911666^2 + 551725^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1135535371181 is a prime.
It is a super-2 number, since 2×11355353711812 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1135535371189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567767685590 + 567767685591.
It is an arithmetic number, because the mean of its divisors is an integer number (567767685591).
Almost surely, 21135535371181 is an apocalyptic number.
It is an amenable number.
1135535371181 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135535371181 is an equidigital number, since it uses as much as digits as its factorization.
1135535371181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 189000, while the sum is 44.
The spelling of 1135535371181 in words is "one trillion, one hundred thirty-five billion, five hundred thirty-five million, three hundred seventy-one thousand, one hundred eighty-one".
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