1135604051 has 2 divisors, whose sum is σ = 1135604052. Its totient is φ = 1135604050.

The previous prime is 1135604039. The next prime is 1135604053. The reversal of 1135604051 is 1504065311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1135604051 is a prime.

It is a super-2 number, since 2×1135604051² = 2579193121295221202, which contains 22 as substring.

Together with 1135604053, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1135604051.

It is not a weakly prime, because it can be changed into another prime (1135604053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567802025 + 567802026.

It is an arithmetic number, because the mean of its divisors is an integer number (567802026).

Almost surely, 2^1135604051 is an apocalyptic number.

1135604051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135604051 is an equidigital number, since it uses as much as digits as its factorization.

1135604051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

The square root of 1135604051 is about 33698.7247681570. The cubic root of 1135604051 is about 1043.2994482378.

Adding to 1135604051 its reverse (1504065311), we get a palindrome (2639669362).

The spelling of 1135604051 in words is "one billion, one hundred thirty-five million, six hundred four thousand, fifty-one".