Base | Representation |
---|---|
bin | 11001110100100110001011… |
… | …000110111001000111011011 |
3 | 112220002202120102110211011221 |
4 | 121310212023012321013123 |
5 | 104341124233403111441 |
6 | 1041311144441032511 |
7 | 32630561355441016 |
oct | 3164461306710733 |
9 | 486082512424157 |
10 | 113565564113371 |
11 | 33204981326127 |
12 | 108a1925785737 |
13 | 4b4a25737a286 |
14 | 200886189637d |
15 | d1e17aa238d1 |
hex | 67498b1b91db |
113565564113371 has 2 divisors, whose sum is σ = 113565564113372. Its totient is φ = 113565564113370.
The previous prime is 113565564113369. The next prime is 113565564113377. The reversal of 113565564113371 is 173311465565311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113565564113371 - 21 = 113565564113369 is a prime.
Together with 113565564113369, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (113565564113377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56782782056685 + 56782782056686.
It is an arithmetic number, because the mean of its divisors is an integer number (56782782056686).
Almost surely, 2113565564113371 is an apocalyptic number.
113565564113371 is a deficient number, since it is larger than the sum of its proper divisors (1).
113565564113371 is an equidigital number, since it uses as much as digits as its factorization.
113565564113371 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3402000, while the sum is 52.
The spelling of 113565564113371 in words is "one hundred thirteen trillion, five hundred sixty-five billion, five hundred sixty-four million, one hundred thirteen thousand, three hundred seventy-one".
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