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1135663512013 is a prime number
BaseRepresentation
bin10000100001101010110…
…100011111100111001101
311000120100100020220001001
4100201222310133213031
5122101314324341023
62225414442220301
7145022541402142
oct20415264374715
94016310226031
101135663512013
113a86a549a468
121641234b4691
13831286041c4
143cd75b703c9
151e81b8e76ad
hex1086ad1f9cd

1135663512013 has 2 divisors, whose sum is σ = 1135663512014. Its totient is φ = 1135663512012.

The previous prime is 1135663512001. The next prime is 1135663512059. The reversal of 1135663512013 is 3102153665311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 859814816644 + 275848695369 = 927262^2 + 525213^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1135663512013 is a prime.

It is a super-2 number, since 2×11356635120132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1135663512073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567831756006 + 567831756007.

It is an arithmetic number, because the mean of its divisors is an integer number (567831756007).

Almost surely, 21135663512013 is an apocalyptic number.

It is an amenable number.

1135663512013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1135663512013 is an equidigital number, since it uses as much as digits as its factorization.

1135663512013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48600, while the sum is 37.

The spelling of 1135663512013 in words is "one trillion, one hundred thirty-five billion, six hundred sixty-three million, five hundred twelve thousand, thirteen".