Base | Representation |
---|---|
bin | 10101001001110110… |
… | …01000011010100111 |
3 | 1002022111000020121021 |
4 | 22210323020122213 |
5 | 141224331231413 |
6 | 5114533432011 |
7 | 551302022443 |
oct | 124473103247 |
9 | 32274006537 |
10 | 11356898983 |
11 | 48a8745331 |
12 | 224b49b607 |
13 | 10bcb57a91 |
14 | 79a455823 |
15 | 46708c18d |
hex | 2a4ec86a7 |
11356898983 has 2 divisors, whose sum is σ = 11356898984. Its totient is φ = 11356898982.
The previous prime is 11356898941. The next prime is 11356898999. The reversal of 11356898983 is 38989865311.
11356898983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11356898983 - 29 = 11356898471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11356898923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5678449491 + 5678449492.
It is an arithmetic number, because the mean of its divisors is an integer number (5678449492).
Almost surely, 211356898983 is an apocalyptic number.
11356898983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11356898983 is an equidigital number, since it uses as much as digits as its factorization.
11356898983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 11197440, while the sum is 61.
The spelling of 11356898983 in words is "eleven billion, three hundred fifty-six million, eight hundred ninety-eight thousand, nine hundred eighty-three".
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