Base | Representation |
---|---|
bin | 10000100010001110110… |
… | …101110101001001011011 |
3 | 11000121220110102001010022 |
4 | 100202032311311021123 |
5 | 122104034031422024 |
6 | 2225554431141055 |
7 | 145043530204433 |
oct | 20421665651133 |
9 | 4017813361108 |
10 | 1136267842139 |
11 | 3a8985635651 |
12 | 16427197478b |
13 | 831c38879b1 |
14 | 3cdd21232c3 |
15 | 1e8549bd35e |
hex | 1088ed7525b |
1136267842139 has 2 divisors, whose sum is σ = 1136267842140. Its totient is φ = 1136267842138.
The previous prime is 1136267842121. The next prime is 1136267842153. The reversal of 1136267842139 is 9312487626311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1136267842139 - 232 = 1131972874843 is a prime.
It is a super-2 number, since 2×11362678421392 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1136267842109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 568133921069 + 568133921070.
It is an arithmetic number, because the mean of its divisors is an integer number (568133921070).
Almost surely, 21136267842139 is an apocalyptic number.
1136267842139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1136267842139 is an equidigital number, since it uses as much as digits as its factorization.
1136267842139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2612736, while the sum is 53.
The spelling of 1136267842139 in words is "one trillion, one hundred thirty-six billion, two hundred sixty-seven million, eight hundred forty-two thousand, one hundred thirty-nine".
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