Base | Representation |
---|---|
bin | 11001110101101111001110… |
… | …101001100000011001101111 |
3 | 112220101021001012222200020112 |
4 | 121311233032221200121233 |
5 | 104343420411202000413 |
6 | 1041411200321210235 |
7 | 32636336266255124 |
oct | 3165571651403157 |
9 | 486337035880215 |
10 | 113644006671983 |
11 | 33235175089467 |
12 | 108b4b77a9097b |
13 | 4b5477892a628 |
14 | 200c58385874b |
15 | d2121c3ed2a8 |
hex | 675bcea6066f |
113644006671983 has 2 divisors, whose sum is σ = 113644006671984. Its totient is φ = 113644006671982.
The previous prime is 113644006671973. The next prime is 113644006672013. The reversal of 113644006671983 is 389176600446311.
It is a weak prime.
It is an emirp because it is prime and its reverse (389176600446311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113644006671983 - 210 = 113644006670959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113644006671973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56822003335991 + 56822003335992.
It is an arithmetic number, because the mean of its divisors is an integer number (56822003335992).
Almost surely, 2113644006671983 is an apocalyptic number.
113644006671983 is a deficient number, since it is larger than the sum of its proper divisors (1).
113644006671983 is an equidigital number, since it uses as much as digits as its factorization.
113644006671983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15676416, while the sum is 59.
The spelling of 113644006671983 in words is "one hundred thirteen trillion, six hundred forty-four billion, six million, six hundred seventy-one thousand, nine hundred eighty-three".
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