Base | Representation |
---|---|
bin | 10000100010101110111… |
… | …000100000000001101101 |
3 | 11000200021220221110200012 |
4 | 100202232320200001231 |
5 | 122111134141203343 |
6 | 2230124033143005 |
7 | 145063045401356 |
oct | 20425670400155 |
9 | 4020256843605 |
10 | 1136805412973 |
11 | 3a913102356a |
12 | 1643a19baa65 |
13 | 8327b065a49 |
14 | 3d043698d2d |
15 | 1e886ca8718 |
hex | 108aee2006d |
1136805412973 has 2 divisors, whose sum is σ = 1136805412974. Its totient is φ = 1136805412972.
The previous prime is 1136805412949. The next prime is 1136805413027. The reversal of 1136805412973 is 3792145086311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1135531065769 + 1274347204 = 1065613^2 + 35698^2 .
It is a cyclic number.
It is not a de Polignac number, because 1136805412973 - 218 = 1136805150829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1136805412913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 568402706486 + 568402706487.
It is an arithmetic number, because the mean of its divisors is an integer number (568402706487).
It is a 2-persistent number, because it is pandigital, and so is 2⋅1136805412973 = 2273610825946, but 3⋅1136805412973 = 3410416238919 is not.
Almost surely, 21136805412973 is an apocalyptic number.
It is an amenable number.
1136805412973 is a deficient number, since it is larger than the sum of its proper divisors (1).
1136805412973 is an equidigital number, since it uses as much as digits as its factorization.
1136805412973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 50.
The spelling of 1136805412973 in words is "one trillion, one hundred thirty-six billion, eight hundred five million, four hundred twelve thousand, nine hundred seventy-three".
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