Base | Representation |
---|---|
bin | 1010010110010010001000… |
… | …0101101011000101101111 |
3 | 1111021201110012222010221002 |
4 | 2211210202011223011233 |
5 | 2442404010202422123 |
6 | 40110541551230515 |
7 | 2253012652435016 |
oct | 245444205530557 |
9 | 44251405863832 |
10 | 11377940279663 |
11 | 36973a2735981 |
12 | 133915521843b |
13 | 646c20730829 |
14 | 2b49a3a8da7d |
15 | 14ae765c9528 |
hex | a592216b16f |
11377940279663 has 2 divisors, whose sum is σ = 11377940279664. Its totient is φ = 11377940279662.
The previous prime is 11377940279647. The next prime is 11377940279677. The reversal of 11377940279663 is 36697204977311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11377940279663 - 24 = 11377940279647 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11377940279663.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11377940279623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5688970139831 + 5688970139832.
It is an arithmetic number, because the mean of its divisors is an integer number (5688970139832).
Almost surely, 211377940279663 is an apocalyptic number.
11377940279663 is a deficient number, since it is larger than the sum of its proper divisors (1).
11377940279663 is an equidigital number, since it uses as much as digits as its factorization.
11377940279663 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72013536, while the sum is 65.
The spelling of 11377940279663 in words is "eleven trillion, three hundred seventy-seven billion, nine hundred forty million, two hundred seventy-nine thousand, six hundred sixty-three".
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