Base | Representation |
---|---|
bin | 10101001101010110… |
… | …00111001100110101 |
3 | 1002101112020122022001 |
4 | 22212223013030311 |
5 | 141304340113013 |
6 | 5121502535301 |
7 | 552106364122 |
oct | 124653071465 |
9 | 32345218261 |
10 | 11386254133 |
11 | 4913275291 |
12 | 2259297531 |
13 | 10c5c653a7 |
14 | 7a02d7749 |
15 | 469939ddd |
hex | 2a6ac7335 |
11386254133 has 2 divisors, whose sum is σ = 11386254134. Its totient is φ = 11386254132.
The previous prime is 11386254119. The next prime is 11386254161. The reversal of 11386254133 is 33145268311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9826162129 + 1560092004 = 99127^2 + 39498^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11386254133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11386254092 and 11386254101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11386254193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5693127066 + 5693127067.
It is an arithmetic number, because the mean of its divisors is an integer number (5693127067).
Almost surely, 211386254133 is an apocalyptic number.
It is an amenable number.
11386254133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11386254133 is an equidigital number, since it uses as much as digits as its factorization.
11386254133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 51840, while the sum is 37.
The spelling of 11386254133 in words is "eleven billion, three hundred eighty-six million, two hundred fifty-four thousand, one hundred thirty-three".
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